Translating time units in KSP

There are:

60 Kerbin seconds per Kerbin minute
60 Kerbin minutes per Kerbin hour
6 Kerbin hours per Kerbin day
6.43 Kerbin days per Kerbin month
426.08 Kerbin days per Kerbin year

A Kerbin month is defined as the time it takes for the Mun to make one orbit around Kerbin, and a Kerbin year is defined as the time it takes for Kerbin to make one orbit around Kerbol. A Kerbin second is equivalent to an Earth second. Week does not appear to be defined anywhere.

As to the chart, it's fairly self-explanatory, as up until you pass "hours", Kerbin units and Earth units are equivalent. The first section gives absolute orbital time, and the second section gives orbital time relative to Kerbin's values. For example, on Moho, the "Revolutions per Kerbin Year" is 4.15. This means that in the time it takes for Kerbin to complete one orbit of Kerbol, Moho will have completed 4.15 orbits of Kerbol.

I have test this bash script up to 100 years on the ingame mission timer and it seems to work. No leap days encountered, and it seems based on "UT" seconds in the savegame file that a year is precisely 426*6*60*60 seconds.

#!/bin/bash
# Usage: $0 seconds 
# Returns UT elapsed seconds as data/time as seen in the ingame mission clock.
# Fractional seconds are shown, but not shown in the game clock.

UT=`echo $1 | cut -f1 -d'.'`
frac=`echo $1 | cut -f2 -d'.'`

SEC=1
MIN=$(( 60 ))
HOUR=$(( $MIN * 60 ))
DAY=$(( $HOUR * 6 ))
YEAR=$(( $DAY * 426 ))

year=$(( UT / $YEAR ))
year=$(( year + 1 ))

day=$(( UT / $DAY ))
day=$(( $day % 426 ))
day=$(( $day + 1 ))
day=`echo $day | awk '{printf "%02d", $1}'`

hour=$(( UT / $HOUR ))
hour=$(( hour % 6 ))
hour=`echo $hour | awk '{printf "%02d", $1}'`

min=$(( UT / $MIN ))
min=$(( $min % 60 ))
min=`echo $min | awk '{printf "%02d", $1}'`

sec=$(( UT % 60 ))
sec=`echo $sec | awk '{printf "%02d", $1}'`

echo "Y${year},D${day},${hour}:${min}:${sec}.${frac}"